What is the integral from 0 to 2 of-x^3 ?

The integral from 0 to 2 of-x^3 is -4

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integral from 0 to 2 of-x^3

\int_{0}^{2} - x^{3} d x

- 4

Solution steps

\int_{0}^{2} - x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= - [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= - 4

\int (3 x^{3} - 2 x^{2}) d x

3 x^{4} + x^{3} - 21 x^{2}

y = x (25.5)

7 x^{2}

y = (arcsin (sec (x)))^{t a n h (x)}