y=2(x+y)y^'

Lösung

y = 2 (x + y) y^{^{'}}

y = \frac{1 + c _{1} x + 1}{c _{1}}, y = \frac{1 - c _{1} x + 1}{c _{1}}

Schritte zur Lösung

y = 2 (x + y) y^{'} (x)

Solve exact ODE:

y = \frac{1 + c _{1} x + 1}{c _{1}}, y = \frac{1 - c _{1} x + 1}{c _{1}}

y = \frac{1 + c _{1} x + 1}{c _{1}}, y = \frac{1 - c _{1} x + 1}{c _{1}}

x \to 0 lim (100)

\frac{d}{d x} (a x^{2} e^{2 x})

x \to + 8 - lim (\frac{x}{x - 8})

\frac{d}{d x} (\frac{3 x}{x ^{2} + x})

t an g e n t f (x) = \frac{3}{x}, (1, 3)