derivative of ln(ln(x+1))

Lösung

\frac{d}{d x} (ln (ln (x + 1)))

\frac{1}{ln ( x + 1 ) ( x + 1 )}

Schritte zur Lösung

\frac{d}{d x} (ln (ln (x + 1)))

Wende die Kettenregel an:

\frac{1}{ln ( x + 1 )} \frac{d}{d x} (ln (x + 1))

= \frac{1}{ln ( x + 1 )} \frac{d}{d x} (ln (x + 1))

\frac{d}{d x} (ln (x + 1)) = \frac{1}{x + 1}

= \frac{1}{ln ( x + 1 )} \cdot \frac{1}{x + 1}

Vereinfache

\frac{1}{ln ( x + 1 )} \cdot \frac{1}{x + 1} : \frac{1}{ln ( x + 1 ) ( x + 1 )}

= \frac{1}{ln ( x + 1 ) ( x + 1 )}

x \to 1 - lim (\frac{3}{x} - \frac{2}{ln ( x )})

\frac{d}{d t} (A (e^{- t} - e^{- t} t))

\frac{d}{d x} (ln (3^{2 - x^{2}}))

\int_{- 1}^{0} \frac{1}{1 + x} d x

\frac{\partial}{\partial x} (x^{9})