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Beliebt Rechnen >

(x+1)y^'+(2x-1)y=e^{-2x}

Lösung

(x + 1) y^{^{'}} + (2 x - 1) y = e^{- 2 x}

Lösung

y = - \frac{1}{3 e ^{2 x}} + \frac{c _{1} ( x ^{3} + 3 x ^{2} + 3 x + 1 )}{e ^{2 x + 2 + c_{1}}}

Schritte zur Lösung

(x + 1) y^{'} (x) + (2 x - 1) y = e^{- 2 x}

Solve linear ODE:

y = - \frac{1}{3 e ^{2 x}} + \frac{c _{1} ( x ^{3} + 3 x ^{2} + 3 x + 1 )}{e ^{2 x + 2 + c_{1}}}

y = - \frac{1}{3 e ^{2 x}} + \frac{c _{1} ( x ^{3} + 3 x ^{2} + 3 x + 1 )}{e ^{2 x + 2 + c_{1}}}

Graph

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