integral of (x^3)/(sqrt(x^2-4))

Lösung

\int \frac{x ^{3}}{x ^{2} - 4} d x

\frac{1}{3} (x^{2} - 4)^{\frac{3}{2}} + 4 x^{2} - 4 + C

Schritte zur Lösung

\int \frac{x ^{3}}{x ^{2} - 4} d x

Wende U-Substitution an

= \int u^{2} + 4 d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{2} d u + \int 4 d u

\int u^{2} d u = \frac{u ^{3}}{3}

\int 4 d u = 4 u

= \frac{u ^{3}}{3} + 4 u

Setze in

u = x^{2} - 4

ein

= \frac{( x ^{2} - 4 ) ^{3}}{3} + 4 x^{2} - 4

Vereinfache

\frac{( x ^{2} - 4 ) ^{3}}{3} + 4 x^{2} - 4 : \frac{1}{3} (x^{2} - 4)^{\frac{3}{2}} + 4 x^{2} - 4

= \frac{1}{3} (x^{2} - 4)^{\frac{3}{2}} + 4 x^{2} - 4

Füge eine Konstante zur Lösung hinzu

= \frac{1}{3} (x^{2} - 4)^{\frac{3}{2}} + 4 x^{2} - 4 + C

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