y^{''}+6y^'+10y=5t-2

Lösung

y^{^{''}} + 6 y^{^{'}} + 10 y = 5 t - 2

y = e^{- 3 t} (c_{1} cos (t) + c_{2} sin (t)) + \frac{t}{2} - \frac{1}{2}

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 10 y = 5 t - 2

Solve linear ODE:

y = e^{- 3 t} (c_{1} cos (t) + c_{2} sin (t)) + \frac{t}{2} - \frac{1}{2}

y = e^{- 3 t} (c_{1} cos (t) + c_{2} sin (t)) + \frac{t}{2} - \frac{1}{2}

\int_{1}^{3} π (\frac{1}{x} + 1)^{2} d x

y^{2} e^{t} + (e^{t} + 2) y^{^{'}} = 0

\int \frac{x ^{2} + 4 x - 5}{( x ^{2} - 9 ) ( x + 1 )} d x

x \to \infty lim (0^{x})

d er i v a t i v e x^{4} (e^{x})