y^{''}+6y^'+25=0

Lösung

y^{^{''}} + 6 y^{^{'}} + 25 = 0

y = c_{1} + c_{2} e^{- 6 t} - \frac{25 t}{6}

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 25 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 6 t} - \frac{25 t}{6}

y = c_{1} + c_{2} e^{- 6 t} - \frac{25 t}{6}

y^{^{''}} + 6 y^{^{'}} + 10 y = 5 t - 2

\int_{1}^{3} π (\frac{1}{x} + 1)^{2} d x

y^{2} e^{t} + (e^{t} + 2) y^{^{'}} = 0

\int \frac{x ^{2} + 4 x - 5}{( x ^{2} - 9 ) ( x + 1 )} d x

x \to \infty lim (0^{x})