(\partial)/(\partial y)(2x^2-xy-5x+1)

Lösung

\frac{\partial}{\partial y} (2 x^{2} - x y - 5 x + 1)

- x

Schritte zur Lösung

\frac{\partial}{\partial y} (2 x^{2} - x y - 5 x + 1)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{2}) - \frac{\partial}{\partial y} (x y) - \frac{\partial}{\partial y} (5 x) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (2 x^{2}) = 0

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (5 x) = 0

\frac{\partial}{\partial y} (1) = 0

= 0 - x - 0 + 0

Vereinfache

= - x

\int e^{x} 9 - e^{x} d x

\frac{d y}{d x} = - \frac{2 x y + 1}{x ^{2} + 2 y}

\int \frac{2 t ^{2}}{2 t ^{2} + 1} d t

\int θ sin (θ^{2}) d θ

x \to 6 + lim (sec (\frac{π x}{4}))