What is (\partial)/(\partial x)(cos(8xy)) ?

The answer to (\partial)/(\partial x)(cos(8xy)) is -sin(8xy)*8y

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(\partial)/(\partial x)(cos(8xy))

\frac{\partial}{\partial x} (cos (8 x y))

- sin (8 x y) \cdot 8 y

Solution steps

\frac{\partial}{\partial x} (cos (8 x y))

Treat

y

as a constant

Apply the chain rule:

- sin (8 x y) \frac{\partial}{\partial x} (8 x y)

= - sin (8 x y) \frac{\partial}{\partial x} (8 x y)

\frac{\partial}{\partial x} (8 x y) = 8 y

= - sin (8 x y) \cdot 8 y

y = 2 x + 8

\int 1 + 36 x d x

\frac{d}{d t} (a e^{b t})

\frac{\partial}{\partial x} (e^{- t})

What is (\partial)/(\partial x)(cos(8xy)) ?
The answer to (\partial)/(\partial x)(cos(8xy)) is -sin(8xy)*8y