What is the first derivative of y=2x+8 ?

The first derivative of y=2x+8 is 2

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derivative of y=2x+8

derivative of

y = 2 x + 8

2

Solution steps

\frac{d}{d x} (2 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (8)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 + 0

Simplify

= 2

\int 1 + 36 x d x

\frac{d}{d t} (a e^{b t})

\frac{\partial}{\partial x} (e^{- t})

\frac{d}{d x} (\frac{1}{x} + \frac{1}{x ^{2}})