What is the first derivative of 1+x^2 ?

The first derivative of 1+x^2 is 2x

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derivative of 1+x^2

derivative of

1 + x^{2}

2 x

Solution steps

\frac{d}{d x} (1 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

\int_{0}^{9} 4 x - \frac{4 x}{3} d x

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\int_{0}^{\infty} 3 e^{2 x} d x

y \to 0 lim (\frac{4 y ^{5} + 5 y ^{3}}{y ^{4} - y})