What is the integral from 0 to infinity of 3e^{2x} ?

The integral from 0 to infinity of 3e^{2x} is diverges

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integral from 0 to infinity of 3e^{2x}

\int_{0}^{\infty} 3 e^{2 x} d x

diverges

Solution steps

\int_{0}^{\infty} 3 e^{2 x} d x

Compute the indefinite integral:

\int 3 e^{2 x} d x = \frac{3}{2} e^{2 x} + C

Compute the boundaries:

\int_{0}^{\infty} 3 e^{2 x} d x =

diverges

= diverges

y \to 0 lim (\frac{4 y ^{5} + 5 y ^{3}}{y ^{4} - y})

\int - \frac{x}{1 + x} d x

6 - y = x^{2}, y + 8 = x^{2}, x - y + 4 = 0, x - y - 6 = 0

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y (0) = - 2, y^{^{'}} (0) = 4

\frac{d}{d x} (\frac{1}{x + sin ( x )})

What is the integral from 0 to infinity of 3e^{2x} ?
The integral from 0 to infinity of 3e^{2x} is diverges