What is the limit as x approaches infinity of 1-2^x ?

The limit as x approaches infinity of 1-2^x is -infinity

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limit as x approaches infinity of 1-2^x

x \to \infty lim (1 - 2^{x})

- \infty

Solution steps

x \to \infty lim (1 - 2^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (1) - x \to \infty lim (2^{x})

x \to \infty lim (1) = 1

x \to \infty lim (2^{x}) = \infty

= 1 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

\frac{d}{d x} (ln (π))

\int_{0}^{3} (3 t + 4) d t

\int_{- 1}^{1} ln ∣ x ∣ d x

y = \frac{13}{x ^{2} + 5 x + 6}, y = 0, x = 0, x = 1

12 y^{^{''}} - 12 y^{^{'}} + 78 y = 0

What is the limit as x approaches infinity of 1-2^x ?
The limit as x approaches infinity of 1-2^x is -infinity