integral of (x^2)/4-1

解答

\int \frac{x ^{2}}{4} - 1 d x

\frac{x ^{3}}{12} - x + C

求解步骤

\int \frac{x ^{2}}{4} - 1 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{2}}{4} d x - \int 1 d x

\int \frac{x ^{2}}{4} d x = \frac{x ^{3}}{12}

\int 1 d x = x

= \frac{x ^{3}}{12} - x

解答补常数

= \frac{x ^{3}}{12} - x + C

y^{^{''}} + 36 y = - 36 sec (6 t)

\frac{d}{d x} (e^{x} + 1)

d er i v a t i v e (arctan (x))^{2}

\frac{\partial}{\partial x} (x^{6})

\int y e^{- \frac{y}{x}} d y