derivative of sec(2x+tan(2x))

Lösung

\frac{d}{d x} (sec (2 x) + tan (2 x))

sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2

Schritte zur Lösung

\frac{d}{d x} (sec (2 x) + tan (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sec (2 x)) + \frac{d}{d x} (tan (2 x))

\frac{d}{d x} (sec (2 x)) = sec (2 x) tan (2 x) \cdot 2

\frac{d}{d x} (tan (2 x)) = sec^{2} (2 x) \cdot 2

= sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2

\int cos (8 x) d x

f (x) = e^{x} x

y^{^{''}} - 8 y^{^{'}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = 11

\int 5 tan (2 x) ln (cos (2 x)) d x

\frac{\partial}{\partial t} (z y^{2} (t + 1))