integral of cot^2(x)csc(x)

Lösung

\int cot^{2} (x) csc (x) d x

\frac{1}{8} (- cot^{2} (\frac{x}{2}) - 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2})) + C

Schritte zur Lösung

\int cot^{2} (x) csc (x) d x

Wende U-Substitution an

= \int \frac{( 1 - u ^{2} ) ^{2}}{4 u ^{3}} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{( 1 - u ^{2} ) ^{2}}{u ^{3}} d u

Multipliziere aus

\frac{( 1 - u ^{2} ) ^{2}}{u ^{3}} : \frac{1}{u ^{3}} - \frac{2}{u} + u

= \frac{1}{4} \cdot \int \frac{1}{u ^{3}} - \frac{2}{u} + u d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{4} (\int \frac{1}{u ^{3}} d u - \int \frac{2}{u} d u + \int u d u)

\int \frac{1}{u ^{3}} d u = - \frac{1}{2 u ^{2}}

\int \frac{2}{u} d u = 2 ln ∣ u ∣

\int u d u = \frac{u ^{2}}{2}

= \frac{1}{4} (- \frac{1}{2 u ^{2}} - 2 ln ∣ u ∣ + \frac{u ^{2}}{2})

Setze in

u = tan (\frac{x}{2})

ein

= \frac{1}{4} (- \frac{1}{2 tan ^{2} ( \frac{x}{2} )} - 2 ln tan (\frac{x}{2}) + \frac{tan ^{2} ( \frac{x}{2} )}{2})

Vereinfache

\frac{1}{4} (- \frac{1}{2 tan ^{2} ( \frac{x}{2} )} - 2 ln tan (\frac{x}{2}) + \frac{tan ^{2} ( \frac{x}{2} )}{2}) : \frac{1}{8} (- cot^{2} (\frac{x}{2}) - 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2}))

= \frac{1}{8} (- cot^{2} (\frac{x}{2}) - 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2}))

Füge eine Konstante zur Lösung hinzu

= \frac{1}{8} (- cot^{2} (\frac{x}{2}) - 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2})) + C

\frac{\partial}{\partial x} (- e^{2 y} cos (2 x) \cdot 2)

a re a y = x^{4} - x^{2}, y^{2} = x^{2}

y^{^{''}} - 2 y^{^{'}} + \frac{53}{4} y = 0

\frac{d y}{d x} = \frac{( 2 x + sec ^{2} ( x ) )}{2 y}

x \to 2 + lim (\frac{x - 13}{- x + 2})