What is (\partial)/(\partial z)(xsin(yz)) ?

The answer to (\partial)/(\partial z)(xsin(yz)) is xcos(yz)y

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(\partial)/(\partial z)(xsin(yz))

\frac{\partial}{\partial z} (x sin (yz))

x cos (yz) y

Solution steps

\frac{\partial}{\partial z} (x sin (yz))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial z} (sin (yz))

Apply the chain rule:

cos (yz) \frac{\partial}{\partial z} (yz)

= cos (yz) \frac{\partial}{\partial z} (yz)

\frac{\partial}{\partial z} (yz) = y

= x cos (yz) y

\int x arcsin (6 x) d x

\frac{d}{d x} (e^{\frac{3 x}{2}})

x \to π lim (ln (sin (x)))

\int \frac{sec ( z ) tan ( z )}{sec ( z )} d z

(1 - 25 x^{2})^{2} arcsin (5 x)

What is (\partial)/(\partial z)(xsin(yz)) ?
The answer to (\partial)/(\partial z)(xsin(yz)) is xcos(yz)y