What is the limit as x approaches pi of ln(sin(x)) ?

The limit as x approaches pi of ln(sin(x)) is Does not exist

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limit as x approaches pi of ln(sin(x))

x \to π lim (ln (sin (x)))

Does not exist

Solution steps

x \to π lim (ln (sin (x)))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to π + lim (ln (sin (x))) =

Does not exist

x \to π - lim (ln (sin (x))) = - \infty

= Does not exist

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f (x) = \frac{6 x}{2 + x ^{2}}, (2, 2)

What is the limit as x approaches pi of ln(sin(x)) ?
The limit as x approaches pi of ln(sin(x)) is Does not exist