What are the solutions to the equation -x^2+6x+3=0 ?

The solutions to the equation -x^2+6x+3=0 are x=3-2sqrt(3),x=3+2sqrt(3)

Find the zeros of -x^2+6x+3=0

The zeros of -x^2+6x+3=0 are x=3-2sqrt(3),x=3+2sqrt(3)

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- x^{2} + 6 x + 3 = 0

x = 3 - 23, x = 3 + 23

Decimal Notation

x = - 0.46410 \dots, x = 6.46410 \dots

Solution steps

- x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 3 = 43

x_{1, 2} = \frac{- 6 \pm 4 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 4 3}{2 ( - 1 )}, x_{2} = \frac{- 6 - 4 3}{2 ( - 1 )}

x = \frac{- 6 + 4 3}{2 ( - 1 )} : 3 - 23

x = \frac{- 6 - 4 3}{2 ( - 1 )} : 3 + 23

The solutions to the quadratic equation are:

x = 3 - 23, x = 3 + 23

\frac{x + 2}{x ^{2} - 3 x - 10}

4 x^{2} - 33 x + 63

x^{2} - x - 11 = 0

15 x^{2} - 19 x + 6

\frac{3}{∣ 5 - 2 x ∣} < 2

What are the solutions to the equation -x^2+6x+3=0 ?
The solutions to the equation -x^2+6x+3=0 are x=3-2sqrt(3),x=3+2sqrt(3)
Find the zeros of -x^2+6x+3=0
The zeros of -x^2+6x+3=0 are x=3-2sqrt(3),x=3+2sqrt(3)