What are the solutions to the equation x^2-x-11=0 ?

The solutions to the equation x^2-x-11=0 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2

Find the zeros of x^2-x-11=0

The zeros of x^2-x-11=0 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x - 11 = 0

x = \frac{1 + 3 5}{2}, x = \frac{1 - 3 5}{2}

Decimal Notation

x = 3.85410 \dots, x = - 2.85410 \dots

Solution steps

x^{2} - x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 11) = 35

x_{1, 2} = \frac{- ( - 1 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 5}{2 \cdot 1} : \frac{1 + 3 5}{2}

x = \frac{- ( - 1 ) - 3 5}{2 \cdot 1} : \frac{1 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 3 5}{2}, x = \frac{1 - 3 5}{2}

15 x^{2} - 19 x + 6

\frac{3}{∣ 5 - 2 x ∣} < 2

\frac{x}{6} + 2 \geq - 16

8 + \frac{x}{- 4} = 5

x^{6} - 16 x^{2}

What are the solutions to the equation x^2-x-11=0 ?
The solutions to the equation x^2-x-11=0 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2
Find the zeros of x^2-x-11=0
The zeros of x^2-x-11=0 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2