s^2-9s-10=0

解答

s^{2} - 9 s - 10 = 0

s = 10, s = - 1

求解步骤

s^{2} - 9 s - 10 = 0

使用求根公式求解

s_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 10) = 11

s_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 1}

将解分隔开

s_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 1}, s_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 1}

s = \frac{- ( - 9 ) + 11}{2 \cdot 1} : 10

s = \frac{- ( - 9 ) - 11}{2 \cdot 1} : - 1

二次方程组的解是:

s = 10, s = - 1

f a c t or 4 n^{8} - 20 n^{4} + 25

x^{2} - 5 x + 1 = 0

s im pl i f y (4 - 3 i) + (2 i - 8)

- 2 (x + 1) < 2

f a c t or 32 t^{2} - 18 u^{2}