What are the solutions to the equation quadraticformula 3x^2-12x+24=0 ?

The solutions to the equation quadraticformula 3x^2-12x+24=0 are x=2+2i,x=2-2i

Find the zeros of quadraticformula 3x^2-12x+24=0

The zeros of quadraticformula 3x^2-12x+24=0 are x=2+2i,x=2-2i

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quadraticformula

x = 2 + 2 i, x = 2 - 2 i

Solution steps

3 x^{2} - 12 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

Simplify

(- 12)^{2} - 4 \cdot 3 \cdot 24 : 12 i

x_{1, 2} = \frac{- ( - 12 ) \pm 12 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 i}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 12 i}{2 \cdot 3}

x = \frac{- ( - 12 ) + 12 i}{2 \cdot 3} : 2 + 2 i

x = \frac{- ( - 12 ) - 12 i}{2 \cdot 3} : 2 - 2 i

The solutions to the quadratic equation are:

x = 2 + 2 i, x = 2 - 2 i

What are the solutions to the equation quadraticformula 3x^2-12x+24=0 ?
The solutions to the equation quadraticformula 3x^2-12x+24=0 are x=2+2i,x=2-2i
Find the zeros of quadraticformula 3x^2-12x+24=0
The zeros of quadraticformula 3x^2-12x+24=0 are x=2+2i,x=2-2i