What are the solutions to the equation 10x^2=27x-18 ?

The solutions to the equation 10x^2=27x-18 are x= 3/2 ,x= 6/5

Find the zeros of 10x^2=27x-18

The zeros of 10x^2=27x-18 are x= 3/2 ,x= 6/5

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10 x^{2} = 27 x - 18

x = \frac{3}{2}, x = \frac{6}{5}

Decimal Notation

x = 1.5, x = 1.2

Solution steps

10 x^{2} = 27 x - 18

Move

18

to the left side

10 x^{2} + 18 = 27 x

Move

27 x

to the left side

10 x^{2} + 18 - 27 x = 0

Write in the standard form

a x^{2} + b x + c = 0

10 x^{2} - 27 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 10 \cdot 18}{2 \cdot 10}

(- 27)^{2} - 4 \cdot 10 \cdot 18 = 3

x_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 3}{2 \cdot 10}, x_{2} = \frac{- ( - 27 ) - 3}{2 \cdot 10}

x = \frac{- ( - 27 ) + 3}{2 \cdot 10} : \frac{3}{2}

x = \frac{- ( - 27 ) - 3}{2 \cdot 10} : \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{6}{5}

x^{8} + 14 x^{4} y^{2} + 24 y^{4}

6 - ∣ 4 + 4 x ∣ = - 5

\frac{20 !}{3 ! ( 20 - 3 ) !}

6 + 65

What are the solutions to the equation 10x^2=27x-18 ?
The solutions to the equation 10x^2=27x-18 are x= 3/2 ,x= 6/5
Find the zeros of 10x^2=27x-18
The zeros of 10x^2=27x-18 are x= 3/2 ,x= 6/5