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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3x^2+24x+48=-108 ?
- The solutions to the equation 3x^2+24x+48=-108 are x=-4+6i,x=-4-6i
Find the zeros of 3x^2+24x+48=-108
- The zeros of 3x^2+24x+48=-108 are x=-4+6i,x=-4-6i