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Frequently Asked Questions (FAQ)
What are the solutions to the equation factor-y+28+y^2=2y+2y^2 ?
- The solutions to the equation factor-y+28+y^2=2y+2y^2 are y=4,y=-7
Find the zeros of factor-y+28+y^2=2y+2y^2
- The zeros of factor-y+28+y^2=2y+2y^2 are y=4,y=-7