log_{2}(2x+2)=1

Lösung

lo g_{2} (2 x + 2) = 1

x = 0

Schritte zur Lösung

lo g_{2} (2 x + 2) = 1

Wende die log Regel an

2 x + 2 = 2

Löse

2 x + 2 = 2 : x = 0

x = 0

lo g_{4} (x + 6) + lo g_{4} (x) = 2

(x + 12) = ln (x) + ln (12)

lo g_{3} (3) + lo g_{3} (x) = 10

ln (x + 3) - 5 = - 2

lo g_{10} (x) = 18.82