What are the solutions to the equation 1=7x^2+6x ?

The solutions to the equation 1=7x^2+6x are x= 1/7 ,x=-1

Find the zeros of 1=7x^2+6x

The zeros of 1=7x^2+6x are x= 1/7 ,x=-1

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1 = 7 x^{2} + 6 x

x = \frac{1}{7}, x = - 1

Decimal Notation

x = 0.14285 \dots, x = - 1

Solution steps

1 = 7 x^{2} + 6 x

Switch sides

7 x^{2} + 6 x = 1

Move

1

to the left side

7 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

6^{2} - 4 \cdot 7 (- 1) = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 \cdot 7}, x_{2} = \frac{- 6 - 8}{2 \cdot 7}

x = \frac{- 6 + 8}{2 \cdot 7} : \frac{1}{7}

x = \frac{- 6 - 8}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{7}, x = - 1

5 x^{2} + 21 x - 9 = 0

\frac{4}{x - 2} + \frac{x}{x + 2} \leq \frac{8 x}{x ^{2} - 4}

\frac{300}{( 1 + 0.06 ) ^{10}}

2 x + 4 = 8 x

3 (1 - x) = 4 (1 + 2 x) + 5

What are the solutions to the equation 1=7x^2+6x ?
The solutions to the equation 1=7x^2+6x are x= 1/7 ,x=-1
Find the zeros of 1=7x^2+6x
The zeros of 1=7x^2+6x are x= 1/7 ,x=-1