What are the solutions to the equation 5x^2+21x-9=0 ?

The solutions to the equation 5x^2+21x-9=0 are x=(-21+3sqrt(69))/(10),x=(-21-3sqrt(69))/(10)

Find the zeros of 5x^2+21x-9=0

The zeros of 5x^2+21x-9=0 are x=(-21+3sqrt(69))/(10),x=(-21-3sqrt(69))/(10)

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5 x^{2} + 21 x - 9 = 0

x = \frac{- 21 + 3 69}{10}, x = \frac{- 21 - 3 69}{10}

Decimal Notation

x = 0.39198 \dots, x = - 4.59198 \dots

Solution steps

5 x^{2} + 21 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

2 1^{2} - 4 \cdot 5 (- 9) = 369

x_{1, 2} = \frac{- 21 \pm 3 69}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 21 + 3 69}{2 \cdot 5}, x_{2} = \frac{- 21 - 3 69}{2 \cdot 5}

x = \frac{- 21 + 3 69}{2 \cdot 5} : \frac{- 21 + 3 69}{10}

x = \frac{- 21 - 3 69}{2 \cdot 5} : \frac{- 21 - 3 69}{10}

The solutions to the quadratic equation are:

x = \frac{- 21 + 3 69}{10}, x = \frac{- 21 - 3 69}{10}

\frac{4}{x - 2} + \frac{x}{x + 2} \leq \frac{8 x}{x ^{2} - 4}

\frac{300}{( 1 + 0.06 ) ^{10}}

2 x + 4 = 8 x

3 (1 - x) = 4 (1 + 2 x) + 5

7 (- 3) + 9 (2) > - 3

What are the solutions to the equation 5x^2+21x-9=0 ?
The solutions to the equation 5x^2+21x-9=0 are x=(-21+3sqrt(69))/(10),x=(-21-3sqrt(69))/(10)
Find the zeros of 5x^2+21x-9=0
The zeros of 5x^2+21x-9=0 are x=(-21+3sqrt(69))/(10),x=(-21-3sqrt(69))/(10)