5^{x+3}=7^{4-3x}

Lösung

5^{x + 3} = 7^{4 - 3 x}

x = \frac{4 ln ( 7 ) - 3 ln ( 5 )}{ln ( 1715 )}

Dezimale

x = 0.39683 \dots

Schritte zur Lösung

5^{x + 3} = 7^{4 - 3 x}

Wende Exponentenregel an

(x + 3) ln (5) = (4 - 3 x) ln (7)

Löse

(x + 3) ln (5) = (4 - 3 x) ln (7) : x = \frac{4 ln ( 7 ) - 3 ln ( 5 )}{ln ( 1715 )}

x = \frac{4 ln ( 7 ) - 3 ln ( 5 )}{ln ( 1715 )}

2 7^{x - 1} = 9

12 = 21 e^{20 x}

3^{2 x + 1} = 5 (3^{x}) + 2

1 = e^{c}

e^{\frac{2}{3} t} = e^{10}