9^{x^2-7x}=27^{x^2+5}

Lösung

9^{x^{2} - 7 x} = 2 7^{x^{2} + 5}

x = - 7 - 34, x = - 7 + 34

Dezimale

x = - 12.83095 \dots, x = - 1.16904 \dots

Schritte zur Lösung

9^{x^{2} - 7 x} = 2 7^{x^{2} + 5}

Wende Exponentenregel an

2 (x^{2} - 7 x) = 3 (x^{2} + 5)

Löse

2 (x^{2} - 7 x) = 3 (x^{2} + 5) : x = - 7 - 34, x = - 7 + 34

x = - 7 - 34, x = - 7 + 34

16 = 2^{x - 3}

so l v e f or x, e^{x y} + x y = 2

7^{5 x + 7} = 3

1 1^{2 x} = 12 1^{3 x + 1}

12 5^{3 x - 4} = 62 5^{- 3}