What are the solutions to the equation x^2+10x-12=0 ?

The solutions to the equation x^2+10x-12=0 are x=-5+sqrt(37),x=-5-sqrt(37)

Find the zeros of x^2+10x-12=0

The zeros of x^2+10x-12=0 are x=-5+sqrt(37),x=-5-sqrt(37)

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x^{2} + 10 x - 12 = 0

x = - 5 + 37, x = - 5 - 37

Decimal Notation

x = 1.08276 \dots, x = - 11.08276 \dots

Solution steps

x^{2} + 10 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 12) = 237

x_{1, 2} = \frac{- 10 \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 37}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 37}{2 \cdot 1}

x = \frac{- 10 + 2 37}{2 \cdot 1} : - 5 + 37

x = \frac{- 10 - 2 37}{2 \cdot 1} : - 5 - 37

The solutions to the quadratic equation are:

x = - 5 + 37, x = - 5 - 37

∣ 4 x - 2 ∣ = 11

x^{2} - 3 x^{1} > 0

2 x^{4} + 9 x^{3} + 13 x^{2} + 81 x - 45

- 31 p + 79 > - 59 p + 81

- 1 - (- 3)

What are the solutions to the equation x^2+10x-12=0 ?
The solutions to the equation x^2+10x-12=0 are x=-5+sqrt(37),x=-5-sqrt(37)
Find the zeros of x^2+10x-12=0
The zeros of x^2+10x-12=0 are x=-5+sqrt(37),x=-5-sqrt(37)