What are the solutions to the equation 10x^2-24x-152=0 ?

The solutions to the equation 10x^2-24x-152=0 are x=(2(3+2sqrt(26)))/5 ,x=(2(3-2sqrt(26)))/5

Find the zeros of 10x^2-24x-152=0

The zeros of 10x^2-24x-152=0 are x=(2(3+2sqrt(26)))/5 ,x=(2(3-2sqrt(26)))/5

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10 x^{2} - 24 x - 152 = 0

x = \frac{2 ( 3 + 2 26 )}{5}, x = \frac{2 ( 3 - 2 26 )}{5}

Decimal Notation

x = 5.27921 \dots, x = - 2.87921 \dots

Solution steps

10 x^{2} - 24 x - 152 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 10 ( - 152 )}{2 \cdot 10}

(- 24)^{2} - 4 \cdot 10 (- 152) = 1626

x_{1, 2} = \frac{- ( - 24 ) \pm 16 26}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 16 26}{2 \cdot 10}, x_{2} = \frac{- ( - 24 ) - 16 26}{2 \cdot 10}

x = \frac{- ( - 24 ) + 16 26}{2 \cdot 10} : \frac{2 ( 3 + 2 26 )}{5}

x = \frac{- ( - 24 ) - 16 26}{2 \cdot 10} : \frac{2 ( 3 - 2 26 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 3 + 2 26 )}{5}, x = \frac{2 ( 3 - 2 26 )}{5}

2 x^{2} - 10 x - 12

24 \cdot 3

(4 x - 2)^{2} = 17

3 c^{2} + 10 c - 8

- 35 p - 45

What are the solutions to the equation 10x^2-24x-152=0 ?
The solutions to the equation 10x^2-24x-152=0 are x=(2(3+2sqrt(26)))/5 ,x=(2(3-2sqrt(26)))/5
Find the zeros of 10x^2-24x-152=0
The zeros of 10x^2-24x-152=0 are x=(2(3+2sqrt(26)))/5 ,x=(2(3-2sqrt(26)))/5