What are the solutions to the equation (4x-2)^2=17 ?

The solutions to the equation (4x-2)^2=17 are x=(sqrt(17)+2)/4 ,x=(-sqrt(17)+2)/4

Find the zeros of (4x-2)^2=17

The zeros of (4x-2)^2=17 are x=(sqrt(17)+2)/4 ,x=(-sqrt(17)+2)/4

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(4 x - 2)^{2} = 17

x = \frac{17 + 2}{4}, x = \frac{- 17 + 2}{4}

Decimal Notation

x = 1.53077 \dots, x = - 0.53077 \dots

Solution steps

(4 x - 2)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 2 = 17 : x = \frac{17 + 2}{4}

Solve

4 x - 2 = - 17 : x = \frac{- 17 + 2}{4}

The solutions to the quadratic equation are:

x = \frac{17 + 2}{4}, x = \frac{- 17 + 2}{4}

3 c^{2} + 10 c - 8

- 35 p - 45

(\frac{1}{3})^{x} \cdot (\frac{6}{5})^{x}

3^{- 3} \cdot 3^{- 2}

(6 x^{3}) (3 x y)^{- 1}

What are the solutions to the equation (4x-2)^2=17 ?
The solutions to the equation (4x-2)^2=17 are x=(sqrt(17)+2)/4 ,x=(-sqrt(17)+2)/4
Find the zeros of (4x-2)^2=17
The zeros of (4x-2)^2=17 are x=(sqrt(17)+2)/4 ,x=(-sqrt(17)+2)/4