What are the solutions to the equation x^2+11x+15=-3 ?

The solutions to the equation x^2+11x+15=-3 are x=-2,x=-9

Find the zeros of x^2+11x+15=-3

The zeros of x^2+11x+15=-3 are x=-2,x=-9

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x^{2} + 11 x + 15 = - 3

x = - 2, x = - 9

Solution steps

x^{2} + 11 x + 15 = - 3

Move

3

to the left side

x^{2} + 11 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 18 = 7

x_{1, 2} = \frac{- 11 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 7}{2 \cdot 1}, x_{2} = \frac{- 11 - 7}{2 \cdot 1}

x = \frac{- 11 + 7}{2 \cdot 1} : - 2

x = \frac{- 11 - 7}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 2, x = - 9

- 2 p^{2} + 4000 p = 0

3 x - 5 \geq 16

4 x^{2} + 8 x + 16

4 x^{2} - 15 x - 25 = 0

9 x + 10 = 7 x

What are the solutions to the equation x^2+11x+15=-3 ?
The solutions to the equation x^2+11x+15=-3 are x=-2,x=-9
Find the zeros of x^2+11x+15=-3
The zeros of x^2+11x+15=-3 are x=-2,x=-9