What are the solutions to the equation 4x^2-15x-25=0 ?

The solutions to the equation 4x^2-15x-25=0 are x=5,x=-5/4

Find the zeros of 4x^2-15x-25=0

The zeros of 4x^2-15x-25=0 are x=5,x=-5/4

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4 x^{2} - 15 x - 25 = 0

x = 5, x = - \frac{5}{4}

Solution steps

4 x^{2} - 15 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 4 ( - 25 )}{2 \cdot 4}

(- 15)^{2} - 4 \cdot 4 (- 25) = 25

x_{1, 2} = \frac{- ( - 15 ) \pm 25}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 25}{2 \cdot 4}, x_{2} = \frac{- ( - 15 ) - 25}{2 \cdot 4}

x = \frac{- ( - 15 ) + 25}{2 \cdot 4} : 5

x = \frac{- ( - 15 ) - 25}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{5}{4}

9 x + 10 = 7 x

\frac{125 - 7}{35 - 5}

16 y^{2} x^{2} + 24 y x^{2} + 9 x^{2}

- 8 m - 12 > - 5 (m - 8) - 3 (m - 7)

\frac{5}{6} + \frac{7}{9} \cdot (\frac{4}{3} - \frac{1}{2})

What are the solutions to the equation 4x^2-15x-25=0 ?
The solutions to the equation 4x^2-15x-25=0 are x=5,x=-5/4
Find the zeros of 4x^2-15x-25=0
The zeros of 4x^2-15x-25=0 are x=5,x=-5/4