erweitern ((x-1)^{4n}(x^3+8)(x-4))/((x^2-2x+2))

Lösung

erweitern

\frac{( x - 1 ) ^{4 n} ( x ^{3} + 8 ) ( x - 4 )}{( x ^{2} - 2 x + 2 )}

\frac{x ^{4} ( x - 1 ) ^{4 n} - 4 x ^{3} ( x - 1 ) ^{4 n} + 8 x ( x - 1 ) ^{4 n} - 32 ( x - 1 ) ^{4 n}}{x ^{2} - 2 x + 2}

Schritte zur Lösung

\frac{( x - 1 ) ^{4 n} ( x ^{3} + 8 ) ( x - 4 )}{x ^{2} - 2 x + 2}

Multipliziere aus

(x - 1)^{4 n} (x^{3} + 8) (x - 4) : x^{4} (x - 1)^{4 n} - 4 x^{3} (x - 1)^{4 n} + 8 x (x - 1)^{4 n} - 32 (x - 1)^{4 n}

= \frac{x ^{4} ( x - 1 ) ^{4 n} - 4 x ^{3} ( x - 1 ) ^{4 n} + 8 x ( x - 1 ) ^{4 n} - 32 ( x - 1 ) ^{4 n}}{x ^{2} - 2 x + 2}

e x p an d A B + A (C D + C D^{^{'}})

e x p an d A (1, 3) B (2, - 5)

e x p an d (3 e^{3 t} + 4 e^{- 4 t})^{3}

e x p an d \frac{x ^{2} - 2 x + 3}{( x - 3 ) ( x ^{2} + 9 )}

e x p an d (e^{t} - 1)^{3}