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受欢迎的代数 >

solvefor a,-Ba+9=Q^2a

解答

求解

a, - B a + 9 = Q^{2} a

解答

a = \frac{9}{B + Q ^{2}}; B \neq = - Q^{2}

求解步骤

- B a + 9 = Q^{2} a

将

9

到右边

- B a = Q^{2} a - 9

将

Q^{2} a

para o lado esquerdo

- B a - Q^{2} a = - 9

分解

- B a - Q^{2} a : - a (B + Q^{2})

- a (B + Q^{2}) = - 9

两边除以

- (B + Q^{2}); B \neq = - Q^{2}

a = \frac{9}{B + Q ^{2}}; B \neq = - Q^{2}

作图

流行的例子

solvefor x,2x+9y=36

so l v e f or x, 2 x + 9 y = 36

solvefor x,5x-8y=-29

so l v e f or x, 5 x - 8 y = - 29

4(x-2)-5(2-3x)=4(2x-6)

4 (x - 2) - 5 (2 - 3 x) = 4 (2 x - 6)

2 x + 7 = 19

x+(3x-9)/5 =4-(5x-12)/3

x + \frac{3 x - 9}{5} = 4 - \frac{5 x - 12}{3}