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人気のある代数 >

k(x)=-x^2-3,k(1)

解

k (x) = - x^{2} - 3, k (1)

解

x = - \frac{k + k ^{2} - 12}{2}, x = - \frac{k - k ^{2} - 12}{2}

解答ステップ

k (x) = - x^{2} - 3

改良

k x = - x^{2} - 3

辺を交換する

- x^{2} - 3 = k x

k x

を左側に移動します

- x^{2} - 3 - k x = 0

標準的な形式で書く

a x^{2} + b x + c = 0

- x^{2} - k x - 3 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - k ) \pm ( - k ) ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

簡素化

(- k)^{2} - 4 (- 1) (- 3) : k^{2} - 12

x_{1, 2} = \frac{- ( - k ) \pm k ^{2} - 12}{2 ( - 1 )}

解を分離する

x_{1} = \frac{- ( - k ) + k ^{2} - 12}{2 ( - 1 )}, x_{2} = \frac{- ( - k ) - k ^{2} - 12}{2 ( - 1 )}

x = \frac{- ( - k ) + k ^{2} - 12}{2 ( - 1 )} : - \frac{k + k ^{2} - 12}{2}

x = \frac{- ( - k ) - k ^{2} - 12}{2 ( - 1 )} : - \frac{k - k ^{2} - 12}{2}

二次equationの解:

x = - \frac{k + k ^{2} - 12}{2}, x = - \frac{k - k ^{2} - 12}{2}

グラフ

人気の例

9 a^{2} + a + 4 = 0

completesquare x^2-12x+40

co m pl e t es q u a re x^{2} - 12 x + 40

(x^2)/4-9/16 =0

\frac{x ^{2}}{4} - \frac{9}{16} = 0

3 r^{2} - r - 7 = 0

(2x-3)^2+(x+3)(x-5)=0

(2 x - 3)^{2} + (x + 3) (x - 5) = 0