-x^2(2)-4+4(2)-2x=0

解

- x^{2} (2) - 4 + 4 (2) - 2 x = 0

x = - 2, x = 1

解答ステップ

- x^{2} (2) - 4 + 4 (2) - 2 x = 0

拡張

- x^{2} (2) - 4 + 4 (2) - 2 x : - 2 x^{2} - 2 x + 4

- 2 x^{2} - 2 x + 4 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

(- 2)^{2} - 4 (- 2) \cdot 4 = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 ( - 2 )}

解を分離する

x_{1} = \frac{- ( - 2 ) + 6}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 6}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 6}{2 ( - 2 )} : - 2

x = \frac{- ( - 2 ) - 6}{2 ( - 2 )} : 1

二次equationの解:

x = - 2, x = 1