|2x^2-3x-1|=2

Lösung

2 x^{2} - 3 x - 1 = 2

x = \frac{3 - 33}{4} or x = \frac{1}{2} or x = 1 or x = \frac{3 + 33}{4}

Dezimale

x = - 0.68614 \dots, x = 0.5, x = 1, x = 2.18614 \dots

Schritte zur Lösung

2 x^{2} - 3 x - 1 = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

2 x^{2} - 3 x - 1 = - 2 or 2 x^{2} - 3 x - 1 = 2

2 x^{2} - 3 x - 1 = - 2 or 2 x^{2} - 3 x - 1 = 2

(x = \frac{1}{2} or x = 1) or (x = \frac{3 - 33}{4} or x = \frac{3 + 33}{4})

x = \frac{3 - 33}{4} or x = \frac{1}{2} or x = 1 or x = \frac{3 + 33}{4}

- x^{3} + 8 x^{2} + 9 x > 72

4 > h

- 4 (w + 4) = 3 (w + 4) + 7

f a c t or 4 x y^{2} + 24 x^{2} y^{6}

s im pl i f y \frac{5 ^{9}}{5 ^{3}}