quadraticformula 2x^2-x-3=0

解

2 x^{2} - x - 3 = 0

x = \frac{3}{2}, x = - 1

十進法表記

x = 1.5, x = - 1

解答ステップ

2 x^{2} - x - 3 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

解を分離する

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

二次equationの解:

x = \frac{3}{2}, x = - 1