What is (x^2-x-2)/(x^2+4x+3)<= 0 ?

The solution to (x^2-x-2)/(x^2+4x+3)<= 0 is -3<x<-1\lor-1<x<= 2

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(x^2-x-2)/(x^2+4x+3)<= 0

\frac{x ^{2} - x - 2}{x ^{2} + 4 x + 3} \leq 0

- 3 < x < - 1 or - 1 < x \leq 2

Interval Notation

(- 3, - 1) \cup (- 1, 2]

Solution steps

\frac{x ^{2} - x - 2}{x ^{2} + 4 x + 3} \leq 0

Factor

\frac{x ^{2} - x - 2}{x ^{2} + 4 x + 3} : \frac{( x + 1 ) ( x - 2 )}{( x + 1 ) ( x + 3 )}

\frac{( x + 1 ) ( x - 2 )}{( x + 1 ) ( x + 3 )} \leq 0

Identify the intervals

- 3 < x < - 1 or - 1 < x \leq 2

1000 (1 + \frac{0.06}{12})^{60}

\frac{1}{10} + \frac{1}{2}

x^{- 2} \cdot x^{2}

114 - 36 k - 6 k^{2} > 0

\frac{4}{5} \cdot (- \frac{1}{4})

What is (x^2-x-2)/(x^2+4x+3)<= 0 ?
The solution to (x^2-x-2)/(x^2+4x+3)<= 0 is -3<x<-1\lor-1<x<= 2