展开 (x^4+2x^2+2)left(x^2-2x+3)

解答

展开

(x^{4} + 2 x^{2} + 2) l e f t (x^{2} - 2 x + 3)

e l x^{6} f t - 2 e l x^{5} f t + 5 e l x^{4} f t - 4 e l x^{3} f t + 8 e l x^{2} f t - 4 e l x f t + 6 e l f t

求解步骤

(x^{4} + 2 x^{2} + 2) l e f t (x^{2} - 2 x + 3)

= e l f t (x^{4} + 2 x^{2} + 2) (x^{2} - 2 x + 3)

乘开

(x^{4} + 2 x^{2} + 2) (x^{2} - 2 x + 3) : x^{6} - 2 x^{5} + 5 x^{4} - 4 x^{3} + 8 x^{2} - 4 x + 6

= l e f t (x^{6} - 2 x^{5} + 5 x^{4} - 4 x^{3} + 8 x^{2} - 4 x + 6)

乘开

l e f t (x^{6} - 2 x^{5} + 5 x^{4} - 4 x^{3} + 8 x^{2} - 4 x + 6) : e l x^{6} f t - 2 e l x^{5} f t + 5 e l x^{4} f t - 4 e l x^{3} f t + 8 e l x^{2} f t - 4 e l x f t + 6 e l f t

= e l x^{6} f t - 2 e l x^{5} f t + 5 e l x^{4} f t - 4 e l x^{3} f t + 8 e l x^{2} f t - 4 e l x f t + 6 e l f t

e x p an d \frac{1}{( 1 - 3 x ) ^{4}}

s im pl i f y (x^{2} + 1) (arctan (x))

e x p an d 2 e^{x} (e^{2} - 1)

e x p an d (- sec (θ) + 2 sec^{3} (θ))^{2}

e x p an d \frac{( x - x cos ( x ) )}{( sin ( 3 x ) ) ^{2}}