簡約 x(x^2-x+1/6)(x-1/2)

解

簡約

x (x^{2} - x + \frac{1}{6}) (x - \frac{1}{2})

\frac{x ( 6 x ^{2} - 6 x + 1 ) ( 2 x - 1 )}{12}

解答ステップ

x (x^{2} - x + \frac{1}{6}) (x - \frac{1}{2})

簡素化

x^{2} - x + \frac{1}{6} : \frac{6 x ^{2} - 6 x + 1}{6}

= x \frac{6 x ^{2} - 6 x + 1}{6} (x - \frac{1}{2})

分数の規則を適用する:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ( 6 x ^{2} - 6 x + 1 ) ( x - \frac{1}{2} )}{6}

簡素化

x (6 x^{2} - 6 x + 1) (x - \frac{1}{2}) : \frac{x ( 6 x ^{2} - 6 x + 1 ) ( x \cdot 2 - 1 )}{2}

= \frac{\frac{x ( 6 x ^{2} - 6 x + 1 ) ( x \cdot 2 - 1 )}{2}}{6}

分数の規則を適用する:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{x ( 6 x ^{2} - 6 x + 1 ) ( x \cdot 2 - 1 )}{2 \cdot 6}

数を乗じる:

2 \cdot 6 = 12

= \frac{x ( 6 x ^{2} - 6 x + 1 ) ( x \cdot 2 - 1 )}{12}

= \frac{x ( 6 x ^{2} - 6 x + 1 ) ( 2 x - 1 )}{12}