What are the solutions to the equation 2x^2-7x=15 ?

The solutions to the equation 2x^2-7x=15 are x=5,x=-3/2

Find the zeros of 2x^2-7x=15

The zeros of 2x^2-7x=15 are x=5,x=-3/2

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2 x^{2} - 7 x = 15

x = 5, x = - \frac{3}{2}

Decimal Notation

x = 5, x = - 1.5

Solution steps

2 x^{2} - 7 x = 15

Move

15

to the left side

2 x^{2} - 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 15) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 2}

x = \frac{- ( - 7 ) + 13}{2 \cdot 2} : 5

x = \frac{- ( - 7 ) - 13}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{2}

y + 9 = 5

1 + \frac{1}{4}

\frac{2 x - 12}{( x - 2 ) ( x - 9 )} < 0

- (\frac{1}{5})^{- 2}

x (x - 5) \geq 0

What are the solutions to the equation 2x^2-7x=15 ?
The solutions to the equation 2x^2-7x=15 are x=5,x=-3/2
Find the zeros of 2x^2-7x=15
The zeros of 2x^2-7x=15 are x=5,x=-3/2