erweitern (2x+1)y'(x)

Lösung

erweitern

(2 x + 1) y^{'} (x)

2 x y' (x) + y' (x)

Schritte zur Lösung

(2 x + 1) y^{'} (x)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = y^{'} (x), b = 2 x, c = 1

= y^{^{'}} (x) 2 x + y^{^{'}} (x) 1

= 2 x y^{^{'}} (x) + 1 y^{^{'}} (x)

Multipliziere:

1 y^{'} (x) = y^{'} (x)

= 2 x y^{^{'}} (x) + y^{^{'}} (x)

e x p an d 4 (3 x^{2} - 2 x y - 5 y^{2})^{2}

e x p an d \frac{3}{2} sin (2 x) (3 cos (2 x) - 1)

e x p an d \frac{d}{d x} ((x + 6) \cdot e^{3 x}) + 4

s im pl i f y (2 x - 2)^{2} (3 x)

e x p an d (y - \frac{7}{4})^{2}