erweitern ((2+x)^2)/4

Lösung

erweitern

\frac{( 2 + x ) ^{2}}{4}

\frac{x ^{2}}{4} + x + 1

Schritte zur Lösung

\frac{( 2 + x ) ^{2}}{4}

(2 + x)^{2} = 4 + 4 x + x^{2}

= \frac{4 + 4 x + x ^{2}}{4}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 + 4 x + x ^{2}}{4} = \frac{4}{4} + \frac{4 x}{4} + \frac{x ^{2}}{4}

= \frac{4}{4} + \frac{4 x}{4} + \frac{x ^{2}}{4}

Wende Regel an

\frac{a}{a} = 1

\frac{4}{4} = 1

= 1 + \frac{4 x}{4} + \frac{x ^{2}}{4}

Teile die Zahlen:

\frac{4}{4} = 1

= 1 + x + \frac{x ^{2}}{4}

Rewrite in standard form

= \frac{x ^{2}}{4} + x + 1

e x p an d (3 - i 3)^{6}

e x p an d cos (θ) (2 sin (θ) + 1)

e x p an d \frac{5}{( s ^{2} + 25 ) ( 1 + 10 e ^{10 t} )}

s im pl i f y - 2 \cdot (\frac{y}{3} + \frac{x}{6})

e x p an d \frac{2 d x}{( x ^{2} - 1 ) ^{2}}