What are the solutions to the equation (4x-3)^2=32 ?

The solutions to the equation (4x-3)^2=32 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4

Find the zeros of (4x-3)^2=32

The zeros of (4x-3)^2=32 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4

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(4 x - 3)^{2} = 32

x = \frac{4 2 + 3}{4}, x = \frac{- 4 2 + 3}{4}

Decimal Notation

x = 2.16421 \dots, x = - 0.66421 \dots

Solution steps

(4 x - 3)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 3 = 32 : x = \frac{4 2 + 3}{4}

Solve

4 x - 3 = - 32 : x = \frac{- 4 2 + 3}{4}

The solutions to the quadratic equation are:

x = \frac{4 2 + 3}{4}, x = \frac{- 4 2 + 3}{4}

\frac{x + 3}{x - 2} \geq 0

3 (x - 2) + 4 = 2 (x + 3)

\frac{3}{4} \cdot 81.71

2 x^{2} - 6 x - 3 = 0

What are the solutions to the equation (4x-3)^2=32 ?
The solutions to the equation (4x-3)^2=32 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4
Find the zeros of (4x-3)^2=32
The zeros of (4x-3)^2=32 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4