What are the solutions to the equation 2x^2-6x-3=0 ?

The solutions to the equation 2x^2-6x-3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2

Find the zeros of 2x^2-6x-3=0

The zeros of 2x^2-6x-3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2

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2 x^{2} - 6 x - 3 = 0

x = \frac{3 + 15}{2}, x = \frac{3 - 15}{2}

Decimal Notation

x = 3.43649 \dots, x = - 0.43649 \dots

Solution steps

2 x^{2} - 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 3) = 215

x_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 15}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 15}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 15}{2 \cdot 2} : \frac{3 + 15}{2}

x = \frac{- ( - 6 ) - 2 15}{2 \cdot 2} : \frac{3 - 15}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 15}{2}, x = \frac{3 - 15}{2}

y - 6 = 0

64 x^{2} - 9

2 x + 4 \geq 24

9 x^{2} + 30 x y + 25 y^{2}

What are the solutions to the equation 2x^2-6x-3=0 ?
The solutions to the equation 2x^2-6x-3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2
Find the zeros of 2x^2-6x-3=0
The zeros of 2x^2-6x-3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2