展開する tan^2(a)(2cos^2(a)+sin^2(a-1))

解

展開する

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1))

tan^{2} (a) sin^{2} (a - 1) + 2 sin^{2} (a)

解答ステップ

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1))

分配法則を適用する:

a (b + c) = ab + a c

tan^{2} (a) (2 cos^{2} (a) + sin^{2} (a - 1)) = tan^{2} (a) \cdot 2 cos^{2} (a) + tan^{2} (a) sin^{2} (a - 1)

= tan^{2} (a) \cdot 2 cos^{2} (a) + tan^{2} (a) sin^{2} (a - 1)

簡素化

tan^{2} (a) \cdot 2 cos^{2} (a) + tan^{2} (a) sin^{2} (a - 1) : tan^{2} (a) sin^{2} (a - 1) + 2 sin^{2} (a)

= tan^{2} (a) sin^{2} (a - 1) + 2 sin^{2} (a)